Question

use python to solve this problem

Problem 3- contains.py: Sub-list containment You will write a function to determine whether a given sub-list" s appears within another given list 1. The problem will guide you through the problem breakdown. Essentially, first you can solve the easier problem if the "sub-list" s appears within 1 at a specific position i. Then Practice goal: Guided practice with modular thinking and programming. Problem 3a Partial equality [5 points] Write a function contains_at that accepts two lists, 1 and s, and an integer i and returns True if and only if the sub-list of 1 starting a index i and ending at index ilen (s)-1 is equal to s. The lists should not be modified in any way. Practice goal: List slices and list equality (the implementation could be a one-liner). Problem 3b - Sub-list [10 points] Write a function contains that accepts two lists, 1 and s, and returns True if and only if 1 contains s at any valid position (i.e, any position 0i<len()). The lists should not be modified in any way. For full credit, your solution must re-use the function contains_at () that you wrote before (even if you wrote it as a one-liner). Practice goal: Another "exists" expression evaluation (which can be viewed as an accumulation with or)

Answer 1

import java.util.*;
class Main {
public static void main(String[] args) {
contains();
}
  
public static boolean contains(){
ArrayList<String> l= new ArrayList<String>();
l.add("1");
l.add("2");
l.add("3");
l.add("4");
  

ArrayList<String> s= new ArrayList<String>();
s.add("3");
s.add("7");
s.add("8");
s.add("9");

//Iterating s list and comparing with l list
for (String temp : s){
if(l.contains(temp)){//if the list contain any value equal return true
System.out.println("true");
return true;
}else{//if the list doesn't contain any value equal return false
System.out.println("false");
return false;
}
}
return false;
}
}