Question

Calculate ?G for the dilution of aqueous HCl from 2.95 M to 0.157 M at 25°C.

Answer 1

delta Go = 0

Q = [H+] [Cl-] / [H+][Cl-]

   = (0.157)^2 / (2.95)^2

Q = 2.83 x 10^-3

delta G = delta Go + RT ln Q

             = 0 + 8.314 x 10^-3 x 298 x ln (2.83 x 10^-3)

delta G = - 14.54 kJ/mol