Free Energy of Dilution
Calculate ΔG for the dilution of aqueous HCl from 1.66 M to 0.109 M at 25°C.
Free Energy of Dilution Calculate ΔG for the dilution of aqueous HCl from 1.66 M to...
Calculate ?G for the dilution of aqueous HCl from 2.95 M to 0.157 M at 25°C.
Calculate the standard free-energy change, ΔG°, for the synthesis of hydrogen chloride gas, HCl, from hydrogen and chlorine gases at 25 °C. ΔG∘f for H2 (g) = 0 kJ; ΔG∘f for Cl2 (g) = 0 kJ; ΔG∘f for HCl (g) = −95.3 kJ. H2(g) + Cl2(g) → 2 HCl(g)
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Free Energy of Dilution Calculate AG for the dilution of aqueous HCl from 1.98 M to 0.260 M at 25°C. 5029.47 mol The process you are considering is: H+ (0) + Cl(aq)H+ (aq) + Cl(aq) (for which AGº=0 i.e. standard states all round--both sides are the same). Now use AG=AGº + RTIN(Q). (Use the actual concentrations to determine Q). Does this agree with what you intuitively know about the spontaneity...
Calculate the free energy ΔG at 25 ∘C for the nonstandard conditions at point C where the reaction quotient Q is 3.58×109.
Free-energy change, ΔG∘, is related to cell potential, E∘, by the equation ΔG∘=−nFE∘ where n is the number of moles of electrons transferred and F=96,500C/(mol e−) is the Faraday constant. When E∘ is measured in volts, ΔG∘ must be in joules since 1 J=1 C⋅V. Calculate the standard cell potential at 25 ∘C for the reaction X(s)+2Y+(aq)→X2+(aq)+2Y(s) where ΔH∘ = -679 kJ and ΔS∘ = -195 J/K .
Calculate the pH and the pOH of an aqueous solution that is 0.050 M in HCl(aq) and 0.070 M in HBr(aq) at 25°C
Calculate the pH and the pOH of an aqueous solution that is 0.040 M in HCl(aq) and 0.085 M in HBr(aq) at 25°C.
Calculate the pH and the pOH of an aqueous solution that is 0.050 M in HCl(aq) and 0.085 M in HBr(aq) at 25 °C. pH = pOH =
Calculate the pH and the pOH of an aqueous solution that is 0.030 M in HCl(aq) and 0.095 M in HBr(aq) at 25 C Thank you in advance
Calculate free energy (ΔG) for transporting 3 moles of Ca2+ from inside to outside of a typical cell. (Using Ca2+ = 1.5mM for outside the cell; [Ca2+] = 0.1 µM for inside the cell; T = 298k; R = 1.987x10^3 kcal/mol/deg; membrane potential (ΔV) = -50 mV (inside negative); Faraday constant = 23.1 kcal/V/mol).