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An 1800-N load Q is applied to the pulley C, which can roll on the cable...

An 1800-N load Q is applied to the pulley C, whichAn 1800-N load Q is applied to the pulley C, which can roll on the cable ACB. The pulley is held in the position shown by a second cable CAD, which passes over the pulley A and supports a load P. Determine (a) the tension in cable ACB, (b) the magnitude of load P.

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Answer #1

Equating the Horizontal forces,
Tacb *( cos(25) - cos(55) ) = P * cos(55)
P = 0.580 Tacb ------1

Equating the Vertical forces,
Tacb *( sin(25) + sin(55) ) + P * sin(55) = 1800
1.242 Tacb + 0.819 P = 1800 ------2

Solving  eq 1 & 2,
Tacb = 1048 N
P = 608 N

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