Question

At t = 0, you have 6.00×109 atoms of 24Na, which undergo beta- decay. 24Na -->...

At t = 0, you have 6.00×109 atoms of 24Na, which undergo beta- decay.

24Na --> 24Mg + e- + V-bar

How much energy is released in this reaction? What is the decay constant? What is the radioactivity at t = 0? What is the radioactivity at t = 1 hour?

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Answer #1

Cr.gtaょ: o.693) o.673] 1.x360o 2 29165x3600 ) A、F チ388 x lot na 1,2ケ. 23:99 u.

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