Question

What will be the maximum negative charge contribution from humic materials expressed in mol/L for a water sample containing 20 mg/L of fulvic acid and 4.0 mg/L of humin? Consider that humic materials can contribute up to 5 mmol of negative charge per gram.

Answer choices: (Please show work).

a) 2.4 x 10^-1 mol/L

b) 4.8 x 10^-2 mol/L

c) 1.2 x 10^-4 mol/L

d) 5.0 x 10^-5 mol/L

e) none of the above

(Please show work)

Answer 1

trumic material consist fulvic Acid and numin. humice malerial a fulvic Acid & humin 20mg) + ung/h [ loosung Ig] 20x10-3g/4 + ux10 g/L Total humic Maternal 2 (20+4) X10 g/L - 245g 24X10-3g/L Moo since nume material can contikate 5mmolg negtive charge per gram so conmbwson by 18m = 5 mmol F = 5410-3 mol/g Connikesion from 24 x103 gemſ 24410 gm / LX SX 103 mol gy 120 X10-6 mol - 11.2010 -4 mohla ang