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(4 pts) Factoring in the spin-spin coupling, draw the expected NMR spectrum of the methyl protons (H* and H) of the propane molecule in this sample. Assume that the coupling constant (J) of the proton H* or H by Hy is 0.01 ppm. Label each peak with its chemical shift value and specify their relative peak area. d.

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Answer #1

d) Propane CH3-CH2-CH3

As the spin-spin coupling is absent, the peaks will not split.

Methyl Paotem Methylene proton 4 0. to 8 Chemical Shift(S Pp m

The difference in the peak lengths is due to:

Methyl group CH3 has three hydrogen atoms connected to one carbon atom and there are two methyl groups present is propane.

Methylene group CH2 has two hydrogen atoms connected to one carbon atom and there is only one methylene group present in propane.

# Peak area ratio

Peak area of Methyl proton / Peak area of Methylene proton = (Length of peak x width of peak)methyl / (Length of peak x width of peak)methylene

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