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y + 155 lb. 4. (15 points) Let Y be a continuous random variable with the probability density function fy() = iSys 4 and fy()
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Ansin Given that, Y is a continuous random variable, then the pdf of yes y Cy) = cly²+1); ley=4 - = 0 ; otheewese @ - flgs is(24) = 1 24 p(7= 3) = ? PlY=3) = f(3) = $(470) lys = (3+1) - 0466*0.41667 - toplanan yeni 004 00(x+2) = 0.41667 © plesys3) =top(2 sy s 3) = 24 [12 - 4-66677 = 0.3056 p (26 46 3) 20.3056 @ P (2 cys 3) = ? p(2<483) Jtly dy - P(x=2) = P(2 cys 3) - P(x=

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