Question

A system is BIBO (bounded-input, bounded-output) stable if every bounded input X(t) yields a bounded output y(t). A system is NOT BIBO stable if there exists any bounded input that results in an unbounded output. By "bounded", we mean that the magnitude of the signal is always less than some finite number. (The signal x(t)=sin(t) would be considered a bounded signal, but X(t)t would not be a bounded signal.) Signals that are infinite in time, but with a magnitude that is always finite, would be considered bounded. Determine whether these systems would be considered BIBO stable, and explain why or why not: ylt)=(x()) yli)=dx(1)

Answer 1

And () = (x (H)² if xet is bounded then there exists a number no such that IX(t) km where is a priorite value => 1 8002 m2 m2 is finite CH) cm? Mis amplies 2 G7s bounded Been Geis also bounded. therefore do bounded=> syp tim is BIBO Stolle (10 YH = da(t) its act's not a combinuous signal roen its degivative P1688 ts not definedao ne pognt of Si continuery. Hence to a bounded, no-anhievous pombales! yo is unbounded thence the system is not BiBo stable