Question

Ib) A capacitor C = 10NF has a stcady sTate voltage across it V= 100 Cos500t +30°) v. Find the steady state curent in the cap
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Answer #1

C = 10 micro farad

voltage across capacitor Vc = 100 cos( 500t +30 ) v

w = 500 rad/sec

Xc = 1/ (wc)

Xc = 1/(500*10*10^-6)

Xc = 200 ohm

Ic = Vc/(-jXc)

Ic = (100<30)/(-j200)

Ic = (100<30)/(200<-90))

Ic = 0.5 < 120

Ic = 0.5 cos(500t + 120) A

steady state current through capacitor Ic = 0.5 cos(500t + 120) A

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