A vertical spring stores 0.930 J in spring potential energy when a 3.5-kg mass is suspended from it.
a) Verify your answer to part A by calculating the spring potential energy when a 7.0-kg mass is attached to the spring.
Potential Energy PE = 1/2kx2
Force F=mg=kx
Therefore x=mg/k
Therefore PE=1/2 k (mg/k)2
= (mg)2/2k
so when the mass gets doubled to 7kg
The potential energy PE will become 4 times.
New PE= 4 x 0.930 = 3.72 J Answer
A vertical spring stores 0.930 J in spring potential energy when a 3.5-kg mass is suspended...
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Part B
If the scale reads 34N when the bottom spring is compressed 30
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