When a 0.58-kg mass is attached to a vertical spring, the spring stretches by 15 cm....
When a 0.58-kg mass is attached to a vertical spring, the spring stretches by 15 cm. How much mass (total) must be attached to the spring to result in a 0.79-s period of oscillation?
Homework Answers
k = m g / x
k = (0.58 * 9.8) / (0.15) = 37.89 N/m
w = 2 pi / T = sqrt [k/m]
m = T2 k / 4 pi2
= (0.792 * 37.89) / (4 pi2)
= 0.598 kg
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