![Steps to find the molasity of all. 0.25L [cs] - and a um [125] = 20 = 8M [x] 2 mol = 8M. Q = 92] [cs2] - This? Ichy 2 mol 0.2](http://img.homeworklib.com/questions/b14ed990-875f-11eb-aaee-43a104ee8e4f.png?x-oss-process=image/resize,w_560)
(a) The research and development unit of an environmental lab is studying the reaction of CH4...
The initial partial pressures of H2, CS2, H2S, and CH4 in the fixed-volume reaction vessel were 378, 252, 68, and 54 torr, respectively. The following reaction was allowed to come to equilibrium 4H2(g) + CS2(g) ⇌ 2H2S(g) + CH4(g) Find the value of Kp given that the total pressure of the equilibrium mixture was 646 torr.
1. At a certain temperature, 0.338 mol CH4 and 0.808 mol H2O is placed in a 4.00 L container. CH4(g)+2H2O(g)????CO2(g)+4H2(g) At equilibrium, 4.89 g CO2 is present. Calculate Kc. 2. At a certain temperature, 0.352 mol CH4 and 0.862 mol H2S are placed in a 1.50 L container. CH4(g)+2H2S(g)????CS2(g)+4H2(g) At equilibrium, 14.5 g CS2 is present. Calculate Kc . 3. At a certain temperature, 0.3211 mol of N2 and 1.501 mol of H2 are placed in a 2.50 L container....
Consider the following equilibrium at 25.0 degrees C and the
information about initial concentrations, and answer the
question:
CH4(g) + 2H2S
(g)
CS2(g)
+ 4H2(g)
In one experiment, 4.00 M CH4, 4.00 M
CS2, 8.00 M H2S and 8.00 M
H2 in a 1.00 L vessel at 1000 degrees C. Kc is
0.036.
After the system is allowed to reach equilibrium, which of the
following concentrations for H
2 and H 2S are
reasonable, given the above initial concentrations? (Only...
calculate the value for the thermodynamic equilibrium constant for the following reaction. CS2 (g) + 4H2 (g) --> CH4 (g) + 2H2S (g) Values for delta Gf: CS2 (g) --> + 66.85 kJ/mol H2 (g) --> + 0.00 kJ/mol CH4 (g) --> - 50.80 kJ/mol H2S (g) --> - 33.33 kJ/mol R = 8.314 x 10^-3 kJ/molK T = 298 K
For the equilibrium, CH4(g) + 2 H2S(g) = CS2(g) + 4H2(g), the concentrations at equilibrium are (CH4) = 0.3322 M, [H2S] = 0.6644 M, [CS2] = 0.0678 M, and [H2] = 0.2712 Mat 1400.0 K. Calculate K. O 0.167 2.50 x 10-3 C) 4.00 - 103
At a certain temperature, 0.361 mol CH4 and 0.972 mol H2S are placed in a 4.00 L container. CH4(g)+2H2S(g)↽−−⇀CS2(g)+4H2(g) At equilibrium,11.3 g CS2 is present. Calculate ?c The answer is NOT 1.17e2, 9.57e-6, or 6.8e-5, Please show me how you got your answer. Thank you.
A) The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) Calculate the equilibrium concentrations of reactant and products when 0.391 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350 K. [CH2Cl2] = M [CH4] = M [CCl4] = M B) The equilibrium constant, Kc, for the following reaction is 1.80×10-4 at 298 K. NH4HS(s) NH3(g) + H2S(g) Calculate the equilibrium concentration of H2S when 0.260 moles of NH4HS(s) are...
A mixture of 0.01341 mol of CH4, 0.01170 mol of
H2S, 0.02118 mol of CS2, and 0.02835 mol of
H2 is placed in a 1.0-L steel pressure vessel at 3416 K.
The following equilibrium is established:
1 CH4(g) + 2 H2S(g) 1
CS2(g) + 4 H2(g)
At equilibrium 0.003198 mol of H2S is found in the
reaction mixture.
- Calculate the equilibrium partial pressures of CH4,
H2S, CS2, and H2.
- Calculate KP for this reaction.
10. 0/4 Submissions Used -/0.09 points A mixture of 0.01270 mol of CH4, 0.01129 mol of H2S, 0.02016 mol of CS2, and 0.02436 mol of H2 is placed in a 1.0-L steel pressure vessel at 3625 K. The following equilibrium is established: 1 CH4(g)2 H2S(g)1CS2 (g ) +4 H2(g) At equilibrium 0.002399 mol of H25 is found in the reaction mixture (a) Calculate the equilibrium partial pressures of CH4, H25, CS2, and H2 Peq(CH4) Peq(H2S) Peq(CS2) Peq(H2) (b) Calculate Kp...
(1). Examine the following equation and discuss the stresses and chemical shifts. CH() + 2H,S.) A CS2(g) + 4H2(g) addition of CS, gas. (b) - removal of H2S gas, (c)- addition of CH4 gas. (d) - Increased pressure. (e)- If the reaction is heated and more CS, gas is evolved. Is the reaction exo-or endo-thermic? (f) - What is the equilibrium constant (K) if the measured concentrations at equilibrium where determined to be [CH] = 0.75 M, [H2) = 1.00...