calculate the value for the thermodynamic equilibrium constant for the following reaction. CS2 (g) + 4H2 (g) --> CH4 (g) + 2H2S (g)
Values for delta Gf:
CS2 (g) --> + 66.85 kJ/mol
H2 (g) --> + 0.00 kJ/mol
CH4 (g) --> - 50.80 kJ/mol
H2S (g) --> - 33.33 kJ/mol
calculate the value for the thermodynamic equilibrium constant for the following reaction. CS2 (g) + 4H2...
For the equilibrium, CH4(g) + 2 H2S(g) = CS2(g) + 4H2(g), the concentrations at equilibrium are (CH4) = 0.3322 M, [H2S] = 0.6644 M, [CS2] = 0.0678 M, and [H2] = 0.2712 Mat 1400.0 K. Calculate K. O 0.167 2.50 x 10-3 C) 4.00 - 103
The equilibrium constant KC for the equation CS2 + 4H2 = CH4 + 2H2S at 900 °C is 27.8. What is the value of KC for the following equation? 1/5CH4 + 2/5 H2S = 1/5CS2 + 4/5H2
QUESTION 2 CH4(8) + 2 H2S(g) = CS2(8) + 4H2(8) A reaction mixture initially contains 0.84 M CH4 and 0.45 M H2S. If the equilibrium concentration of H2 is 0.64 M, find the equilibrium constant (Ke) for the reaction *Please report 3 significant figures. Numbers only. No unit. No scientific notation
The initial partial pressures of H2, CS2, H2S, and CH4 in the fixed-volume reaction vessel were 378, 252, 68, and 54 torr, respectively. The following reaction was allowed to come to equilibrium 4H2(g) + CS2(g) ⇌ 2H2S(g) + CH4(g) Find the value of Kp given that the total pressure of the equilibrium mixture was 646 torr.
(a) The research and development unit of an environmental lab is studying the reaction of CH4 and H2S, two components of natural gas: CH-(g) + 2H2S(g) CS2(g) + 4H2(g) In one experiment, 1.00 mol of CH4, 1.00 mol of CS2, 2.00 mol of H2S and 2.00 mol of H2 are mixed in a 250 mL vessel at 960°C. At this temperature, K = 0.036. (1) Determine the reaction quotient, Qc. (6 marks) (ii) Comment on the obtained Q in Q1(a)...
Consider the following reaction: CH4(g) + 2 H2S(g) ⇌ CS2(g) + 4 H2(g)A reaction mixture initially contains 0.50 M CH4 and 0.75 M H2S. If the equilibrium concentration of CS2 is 0.15 M, what is the equilibrium constant (Kc) for the reaction.Hint: You might need an I.C.E. Table for this one. please show work
A mixture of 0.01341 mol of CH4, 0.01170 mol of
H2S, 0.02118 mol of CS2, and 0.02835 mol of
H2 is placed in a 1.0-L steel pressure vessel at 3416 K.
The following equilibrium is established:
1 CH4(g) + 2 H2S(g) 1
CS2(g) + 4 H2(g)
At equilibrium 0.003198 mol of H2S is found in the
reaction mixture.
- Calculate the equilibrium partial pressures of CH4,
H2S, CS2, and H2.
- Calculate KP for this reaction.
Consider the following reaction: CH4(g) + 2 H2S(g) ⇌ CS2(g) + 4 H2(g) A reaction mixture initially contains 0.800 M CH4 and 0.950 M H2S. If the equilibrium concentration of H2 is 0.440 M, find the equilibrium constant (Kc) for the reaction. A. A) 0.234 B. B) 0.0381 C. C) 2.93 D. D) 10.2 E. E) 0.0112 F. F) none of these
For the following reaction: 2CH4(g) + O2(g) → 2CO(g) + 4H2(g) Compound ΔH°f (kJ mol-1) S° (J mol-1 K-1) CH4 (g) -74.87 188.66 O2 (g) 0.00 205.70 CO (g) -110.53 197.66 H2 (g) 0.00 130.68 Calculate ΔG°rx (in kJ) at 345.31 K for this reaction. Report your answer to two decimal places in standard notation (i.e. 123.45 kJ). Assume ΔH°f and S° do not vary as a function of temperature.
Given the thermodynamic data below, calculate the value of the
equilibrium constant for the reaction shown at 25.0ºC
H₂ (g) + I₂ (g) ⇄ 2 HI (g)
Given the thermodynamic data below, calculate the value of the equilibrium constant for the reaction shown at 25.0°C H2(g) + 12 (g) = 2 HI(g) AH° = -9.48 kJ AS° = +21.79 J/K K= at 25.0°C Check