EEEEE Question 6 Calculate the molarity of the following solutions. (a) 4.739 g RuCl2 dissolved in...

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Question

science chemistry

Answer 1

Answer #1

RuCl₃ molar mass : 207.43 g/mol

Solution contains 4.739 g dissolved in 1.000 L solution .

moles of RuCl₃ : 4.739 g /207.43 g/mol = 0.02285 moles

thus , molarity : 0.02285 moles/ 1.000 L = 0.02285 mole/L or 0.02285 M

Answer 2

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