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In trial one, 61mL of MnO4 were required to titrate 4mL of H2O2. This was in an eviroment with 10mL H2SO4. In trial 2, same conditions except 65.8mL required to titrate it. How can i figure out the percentage of H2O2 in my sample?

Trial 658 mL Au 65.8mL MU
In trial one, 61mL of MnO4 were required to titrat
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Answer #1

Hello, the volumes of the reactants are not enough to determine the porcentage of H2O2 in the sample, the concentration of MnO4 is at least needed, also the grams of sample (total sample) is needed. I think that you have review the data you have available and explain better the steps of the experimentation, because, for example, if I assume the density of H2O2 as 1 g/mL and the reaction took 4 mL therefore there are 4 grams of H2O2, so, how to calculate the porcentage if you don't tell me where the sample came from?.

Regards!!

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