Question

A boy stands at a dark well and wants to investigate how deep this well is. He therefore throws a stone into the well and after 2.6 seconds he hears the sound of the stone hitting the water surface. If the sound velocity is assumed infinitely high and it is assumed that one can ignore the air resistance of the stone. Sound speed at sea level is approximately 340 m / s. Approximately how large a deviation from the above calculated result does it include the sound speed in the calculation? A) 0 to 1 m B) 2 to 3m C) 5 to 10 m D) Over 10 m E) Don't know Please give me a full explanation with calculations

Answer 1

given data time (t) = 2.6 sec sound speed (&) = 340 ml see Soll in If » sound speed not included them 3 det depth of well = do Stone goes down under the gravitational force 4 acceleration = g = 9.81 m/ see so initial velocity 4-0 fat, + 1 g + ² & d, = di = $x 9.81 x (256) = 33.1578 m speed of sound included i if then =)

time (tal = 2.6 + (da 340 time sound to reach the ear to de = fata + 1 X 9.81 (2.6+daj? 340 i do = 35.906 m. so difference = do-d, = 357906 - 33-1578 = 2.7483 m