Question

A wild pig attacks a hunter with a velocity of 5 m/s. At the instant when the pig is at a distance of 100 m the hunter shoots an arrow with an angle of 40° above the horizontal.What is the initial velocity of the arrow to kill the wild pig?

Answer 1

5 m/s 670° 100m

let when arrow will hit the pig then distance from pig to hunter will be 100-x that is equal to range of arrow and let initial velocity of arrow is V

now X = V_pigt = 5*t ..............................(1)

here t is equal to time of flight of arrow

so now we apply projectile eqⁿs

R=u²sin2$\theta$/g

t=2usin$\theta$/g

now 100-x=R

$\Rightarrow$100- V_pigt = R

using formula of R and t and g=9.8 m/s²

$\Rightarrow$100- 5*2Vsin40^o/9.8 = V²sin80^o/9.8

$\Rightarrow$100-0.656V=V²0.1

$\Rightarrow$V²+6.56V-1000=0

solving this eqⁿ we get V= 28.51 m/sec