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Question#3 The double pulley has a mass moment of inertia of 150 ft·lb-s2. If the system is initially at rest, determine the

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Question has been solved by both energy and Newton method...

moment of interia of pulley (J) = 150 ffdby 2. fBD of system M = 10 = St - 35+ equation & T Tz of block & pulley. let ↑ Tz ATfrom 6 e 4 3 3/2006 - 18654) - s1965 +10.14) = 1802. 1170 = 1460.23* [x=0.8 rad/17 Now a = ar = 5X0.8= 4 ft /s2. q=2n = 3x0.8from enersy method! inhal Total enery = final Total energy. mag ho = mghat I muro + I MBY ² + 1 5 w² L Tho=loft 1 ko h ha ha

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