How many faradays are transferred in an electrolytic cell when a current of 2.0 amperes flows...

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Question

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Answer 1

Answer #1

charge Q = i x t = 2 x 43200 = 86400 coloumbs

Now 96485 coloumbs = 1 Farady

86400 coloumbs = ( 86400 /96485) = 0.8955 faradys

hence faradys transferred = 0.8955

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Answer 2

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