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A tensile force of 1,216 lbs is applied to a 10.4 inch long bar that is...

A tensile force of 1,216 lbs is applied to a 10.4 inch long bar that is 0.500 inches in diameter. Use a modulus of elasticity of 15,000,000 psi to calculate the change in length of the bar.

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change in length (Ad) = PL AE P = 1216 lbs L = 10.4 inch A = d= 744x05? - 0. 196 inch? - 1216% 104 0.196x15x106 Al= o. o 6usPlease dear thumpsup for the answer. Thank you

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