2Cl-(aq)+2H2O(l)--->2OH-(aq)+H2(g)+Cl2(g)
is it Cl oxidized, reduced or neither nor
from the reaction, let us split half reaction
2Cl-(aq) --> Cl2(g)
now, balance charges
2Cl-(aq) --> Cl2 + 2e-(aq)
Cl goes from -1 to 0
therefore, it loses 2 electrons, meaning that it is oxidized
therefore, if it oxidizes then it must be acting as a reducing agent
2Cl-(aq)+2H2O(l)--->2OH-(aq)+H2(g)+Cl2(g) is it Cl oxidized, reduced or neither nor
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