Question

Problem 5.58 < 18 of 18 > a Review Part A The turbine develops 150 kW of power, which is transmitted to the gears such that both C and I receive an equal amount. The rotation of the 100-CELELL-diameter A-36 steel shaft is w = 800 rev/min. The journal bearing at allows the shaft to turn freely about its axis. The shear modulus of elasticity for the A-36 steel is 75 GPa (Figure 1) Determine the absolute maximum shear stress in the shaft Express your answer to three significant figures and include the appropriate units, Tess - 9.12 MPa Previous Answers Correct Part B Determine the rotation of end of the shaft relative to E. Express your answer using three significant figures. Figure C 101 Y AZ&) vec O ? p=2.189 Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining < Return to Assignment Provide Feedback

Answer 1

solutions Given details; parta's power = 150 kw CAD receives an equal amounts le; Creives - 50% =0.5 'oo receives -50% =0.5 rotation - 100-mm. shaft w; soorenimo. elasticity for the A-36 steel is - 75 Gpa. we know that; P = Two (50 KW = T ( 80 ) Cimin 60dec) (2 Tirad) sec- 150 kw = 83.733T 150 1900 = 1 * 7 = 1791. 401 T= 1791-400 Nm 83.733 C-receives at T = 1c=1791.40) (0-5) = 895-70 Nm Do receives at T 510 = 17910 401 (0-5) - 895.40 Nm we have to find out the max • Torque in orgico "BC".

" max = Tc - 1791.401(0.5) 1 / 2 (0.054 Imax : 895-700 911281 Mpa 9.812 SX 106 Temax = 9:1281 mpa | any part bi rotation of and B of the shaft-relative to E formula for rotation of and B-of Eis; Pele Elena) Jason (1791-4023) 745 * (4) +o] = 8957.003 I (0-057475)(109) || =G=758109 J-1 (0-05) EIB = 0.012lrad Stadionto te degree_convention de l = 0:4732)