Question

Activity No. Activity Time (weeks) Immediate Predecessors 1 Collect requirements 6 2 Analyze processes 2 1...

Activity No.

Activity

Time (weeks)

Immediate Predecessors

1

Collect requirements

6

2

Analyze processes

2

1

3

Analyze data

4

2

4

Design processes

18

2

5

Design data

6

3

6

Design screens

6

3,4

7

Design reports

12

4,5

8

Program

10

6,7

9

Test and Document

14

7

10

Install

4

8,9

Construct a network diagram & calculate the earliest expected completion time/s

0 0
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Answer #1
ACTIVITY DURATION ES EF LS LF SLACK
1 6 0 6 0 6 0

2

2 6 8 6 8 0
3 4 8 12 16 20 8
4 18 8 26 8 26 0
5 6 12 18 20 26 8
6 6 26 32 36 42 10
7 12 26 38 26 38 0
8 10 38 48 42 52 4
9 14 38 52 38 52 0
10 4 52 56 52 56 0

FORWARD PASS
We calculate the ES and EF values using a forward pass where the ES of an activity is the maximum EF of all the predecessor activities.

BACKWARD PASS
We calculate the LS and LF values using a backward pass where the LF of the activity is the minimum of all the successor activities.

SLACK
Slack is the value which is determined by subtracting EF from the LF or ES from the LS.

CRITICAL PATH
Critical path is the chain in the project network where the slack value of all the activities is 0, what this means is that any delay in these activities would result in delaying the entire project.

CRITICAL PATH = 1-2-4-7-9-10
DURATION OF PROJECT = 56

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