Here ,
the current in resistor R1 is I1
current in resistor is R2 is I2 ,
using KVL
19 - 7 * I1 - 9 *(I1 - I2) = 0
16 I1 - 9 I2 = 19 ----(1)
again using KVL
- 11 * I2 + 8 - 9 (I2 - I1) = 0
-9 I1 + 20 I2 = 8 ----(2)
solving 1 and 2
I1 = 1.89 A
I2 = 1.25 A
Now,
V(R3) = (1.89 - 1.25) * 9
V(R3) = 5.76 V
voltage across R3 is 5.76 V
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