Question

pls help

R1 R3 R2 w w V14 V3+ V2+ Consider the circuit shown below, where R1= 2 Ohm, R2= 8 Ohm, R3= 5 Ohm, V1= 14 V, V2= 9 V, and V3= 16 V. a) Find the potential difference across R1 Number Units b) Find the magniture of the current through R2 Number Units c) Find the power dissipated in R3 Number Units

Answer 1

From Kirchhoff's loop rule for left loop V-IR-IR-V = 0 14-21, -51, -16=0 21+51, +2 = 0............1 Write Kirchhoff's loop rule for right loop V:-1,R2 -1,R-V = 0 9-81, -51, -16 = 0 812 +51, + 7 = 0...........2 The junction rule is, 1 +12 = 1,.........3 From equ1, equ2 and equ3 11 = 0.136A 12 = -0.591 A 13 = -0.454A (a)The potential difference is, V = IR = (0.136)(2) = 2.72 A b)The magnitude of the current is, 12 = 0.591 A c)The power is, P=IR =(0.454)(5) = 2.27 W