Question

a) Please show all your steps. For the magnitude and phase angle plots, approximate bode diagrams (as provided in the last frequency lecture notes) and use MATLAB to obtain the exact solutions. You will observe that the maximum difference in the solutions are at the corner frequencies! b) Upholding Ethical standard is expected from you. If any ethical violation is detected, appropriate academic measure will be applied. c) Please respect the due date too. 250 1. Given: G(S) = 52 + 50.55 +25 a) Clearly indicate the value of the corner frequencies. (2 pts.) b) Plot the Bode diagram of the magnitude as a function of the frequency. (4 pts. c) Plot the phase angle as a function of frequency. (3 pts) 2. Given: - 6 +16,80 +167000 +1) a) Indicate the corner frequencies. (1 pt.) b) Identify the value of the frequency, if any, where the approximate magnitude graph crosses the frequency axis. (2 pts.) c) Plot the Bode diagram of the magnitude as a function of the frequency. (5 pts.) d) Plot the phase angle as a function of frequency. (3 pts.)

Answer 1

Writing the giving trans for function in pole-zero form ine GC6)= Tit105(3) ] frequency a) b) int By observing at is clear that, the cornor is 5 rad/sec. The intial Magnitudes (M) - 2010g (10) = 2006 Magnitude plot: IMI 1 L odb/dec \-40dbydec . Magnitude mt 20 9 Bodle poste palet : (Asymptotie) ase plot 49 -180°

is . a) clear that By the transfee function, it observing the cornor frequencies are 10, 100, 1000 Antial Magnitude : Moon - 201079) + 20log (in) - 0-20 log Cio) =-2006 Bode plot: Magnitude (к), odb/dec v reodpec 20do/deca yn 10 low Too 1000 1000 hodb/dec -Qodil b) By at observing the w= 1 rad/sec Magnitude plot it is clear that, and w=1000 rad/sec, it crosses the frog.amis. d) Bode phase plot +90° twe 1000 909 -180°