
For the equilibrium N_2O_4(g) 2 NO_2(g), the degree of dissociation, alpha_c, at 298 K is 0.201...
Consider the reaction 2NO_2(g) rightarrow N_2O_4 (g). Using the following data, calculate Delta G degree at 298 K. Delta G degree (NO_2(g)) = 51.84 kJ/mol, Delta G degree (N_2 O_4 (g)) = 98.28 kJ/mol. Calculate Delta G at 298 K if the partial pressures of NO_2 and N_2O_4 are 0.37 atm and 1.62 atm, respectively. Express your answer using one significant figure.
2. For the isomerization reaction, N204(g) + 2NO2(g), the degree of dissociation (a) is 0.201 at equilibrium (25°C and 1 bar). (NOTE: DO NOT simply look up the thermodynamic table for this question. You MUST compute all the quantities using known formula.) (a) Calculate A,G,A,Gº and K at equilibrium. (b) If the equilibrium constant at 100°C is 17.46, is this reaction exothermic or endothermic? (c) Calculate the standard reaction entropy, A. Sº, of this reaction.
Find the equilibrium concentration of N_2O_4(g) [Nitrogen nitroxide] due to the chemical reaction at 25 degree C and 1 atm. N_2O_4(g) doubleheadarrow 2NO_2(g) Using the available data: (a) N_2O_4 (g) doubleheadarrow N_2(g) + 2O_2 (g), Delta G degree_rxn, 1 = Delta G degree_f, N_2O_4 = -23.41 kcal/mol (b) 0.5N_2(g) + O_2(g) doubleheadarrow NO_2(g), Delta G degree_rxn, 2 = -Delta G degree_f, NO_2 = -12.24kcal/mol
Calculate the equilibrium constants K and Kc, the degree of dissociation, alpha for the dissociation of hydrogen gas at 3000 K and 1 bar. The standard molar Gibbs energies of formation of H2(g) and H(g) at 3000 K and 1 bar are 0 and 46.0 kJ/mol, respectively. Assume ideal gas behavior. H2(g) 2 H(g)
Calculate the value of K, at 298 K, for each value of delta G degree. delta G degree = 7.5 kJ/mol delta G degree = -9.0 kJ/mol
At 248 ºC and a total pressure of 1.00 atm the degree of dissociation of SbCl5(g) is alpha = 0.718 for the reaction SbCl5(g) ↔ SbCl3(g) + Cl2(g) . The degree of dissociation alpha is defined as: alpha = (number of moles of SbCl5 dissociated at equilibrium) / (original number of moles of SbCl5) . (a) What is the value of the equilibrium constant K(T) at 248 ºC and 1.00 atm? (b) What is the value of Kx (the equilibrium...
At 248 ºC and a total pressure of 1.00 atm the degree of dissociation of SbCl5(g) is alpha = 0.718 for the reaction SbCl5(g) ↔ SbCl3(g) + Cl2(g) . The degree of dissociation alpha is defined as: alpha = (number of moles of SbCl5 dissociated at equilibrium) / (original number of moles of SbCl5) . (a) What is the value of the equilibrium constant K(T) at 248 ºC and 1.00 atm? (b) What is the value of Kx (the equilibrium...
The equilibrium constant, Kp, for the following reaction is 0.110 at 298 K: NH4HS(s) ->NH3(g) + H2S(g) Calculate the partial pressure of each gas and the total pressure at equilibrium when 0.581 moles of NH4HS(s) is introduced into a 1.00 L vessel at 298 K. Assume that the volume occupied by the solid is negligible. PNH3 = atm PH2S = atm Ptotal = atm
Having problem in solving 3 (iii)
Consider the following reaction at equilibrium at 298 K 2Ag(s) 2HC(g)2AgCl(s) Hag Given the following data at 298 K 4 92.21 95 18 126 90 AHkmole) (i) Calculate Δ. ΔΗ , AS and Kp for the reaction at 298 K () Calculate Kp at 500 K w)If no moles of HCI are present initially, caloulate the partial pressure of H2 at equilibrium at 298 K taking α to be the fraction of dissociation and...
Consider the dissociation of chlorine at 2000 K: Cl2(g) 2 Cl(g) AG 10.162 k mol-1 An equilibrium mixture of both gases has a total pressure of 5.00 bar Determine the partial pressure of both gases in the mixture.