Question

We now attach two output terminals to the circuit from problem 13. The resulting circuit is shown in in Figure 1.40. (a) What is the voltage between the terminals G and H ? (b) What current flows from G to H ? (c) If we connect a wire from G to H, what current flows through the wire and what is the voltage between G and H ?

♡ (le:1.8) We now attach two output terminals to the circuit from problem 13. The resulting circuit is shown in in Figure 1.40. (a) What is the voltage between the terminals G and H? (b) What current flows from G to H? (c) If we connect a wire from G to H, what current flows through the wire and what is the voltage between G and H? A G B C IKI RS RS Vo + H F Ꭱ Ꭼ Ꭱ Ꭰ . Figure 1.40: The circuit for problem 14.

Answer 1

MAAM HMMM @ Applying K.V.1. in loop A BEFA - ů R + lz R + e, R = Vo - 21; R + d2R = Vo -- --0) Applying xovil in loop B C D EB- i R + lz R + iz R - 1₂ R = 0 =) 32R = IR A o l = 3 2 - - - - 2 - Applying K.col. at mode B- I l = l + iz lz=1-12 3 Put value of iz from eq. into ea. - da=3(1-12) 12 = 31, -312 = 412 = 38, et al. = 4 i 6 Put value of i, from eq.6 into eq. 10 - 2x 4 12 R + 12R = Vo iz R 8 +1] =V. 2 SRX L = Vo => =3Vo - ©

Zvo HIR - blz 11 R som eq. - Bivon = big = ls - Vo Voltage between G and H. = Voltage between C&D = іх = V0 XR TIR - Vo b. there is no direct comection betwee- n G to H so no current flows from G to H. C 1 / hiB 3R C R G A in Bruin | | v O. | Votato 3 Brah - FRĒTo سيامحلا D If G and I are connected by a wire then then their is no cenrent flows through the resistor Comected between C & D so we can remove it. - using KV.E: In loof ABEFA- IR+CI-IR+IR = Vo => 3IR-IR EVO ---- using K.V.L. in loop BG HEB- IR+IR - (I-IR=0 = 3TK = IR = I=31 - 2 Put the value of I foom eg. into eg. (1- 3x3IR-IR EVO → SI REVO → I

Since G and H are directly connected by a conducting wire whose resistance is zero (R=0).So voltage between G and H-

V=I, XR = I1 X0 = 0v