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P-0,SkN Mo-0,4kNun P1. 4/2 20=1 A -A a=3cuE2.10M -an 0,3 P-C -4m Reacas 2) FR dish (rald dveu) иO. МОК тax

Forces distribution graph ?

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Solution P O.S kN Мо O.4 kN-m A o g m- o-gm-H ci) Reactions at cantilever point ) reaction forces Reaction mo ment about poin3cm 2CHA N.A MoMent of Inertia T 4cm 4 h 2 2 2 3 =14.583 cm I 2 4 S83 x lo m 2Cm MAX MMa b I - 2 3 o.4xD X 2x16 MAXY MAX 4.S82 4) W(x) WmAx hand Side of bea«u starting fro m Shear force equation o<CO 8 m W(x) So.8 < x < 16 m o. S KN W(K) here Wmax o

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Forces distribution graph ? P-0,SkN Mo-0,4kNun P1. 4/2 2'0=1 A -A a=3cuE2.10M -an 0,3 P-C -4m...
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