Homework Answers
here q = 1.6 x 10-19 C m = 1.672 x 10-27 Kg d = 65 cm R = 0.65 / 2 = 0.325 m
B = 0.820 T delta V = 550 volt
as we know that the maximum K.E.
K.E. = q x delta V
= 1.6 x 10-19 x 550 = 880 x 10-19 J Ans
as we know that the speed of particle
V = qBR / m
= ( 1.6 x 10-19 x 0.820 x 0.325 ) / ( 1.672 x 10-27 )
= 0.2550 x 108 m/s
here V = wR
w = ( 0.2550 x 108 ) / 0.325
= 0.7846 x 108 rad / s Ans
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