Question

Using the Linear Regression Fit Line: y=0.409x+2.963, calculate a forecast for the 18th month. 2 Pts Actuals 12 0.4093x+2 9632 10 Calculate a Forecast for Month 18 18th Month Forecast a) b) Does this look like a good use of a regression approach & why? c) List any concerns you 2 might have if I asked you to forecast month 24 with the data for months 1 through 17 only? 0123456789 10 11 12 13 14 15 16 17 18
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Answer #1

Regression line y=0.409 x+2.963

When x=18

Then, y=0.409 *18 +2.963 =10.325           

So 18th month forecast =10.325

This will be a good approach for the forecasting provided that dependent variable pattern continues as in the past.

He main concerns are that the data after 18th will not be provided and thus the patterns in them is not precise which can lead to some forecast errors.

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