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Q15) This ring has a cross-sectional area of 15 cm as shown in Fig. 3. Find the ampere-turns required to produce a flux of 9

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Dia = 21cm = 0.21m alea a 15%254 m2 rading - 0.21 : 0.105m length to 254 ; 21 0.105 -0.6597 m Mr steel : 700; Mreun = 156 flu

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