C13 NMR Write the structural formula for C5H10O with 17.5q, 23.3q, 68.8d, 125.5d, 135.5d (hint:two different...

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Question

C13 NMR

Write the structural formula for C5H10O with 17.5q, 23.3q, 68.8d, 125.5d, 135.5d (hint:two different functional groups)

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Answer 1

Answer #1

C5H10O has degree o unsaturation dn = ( nC x 2+2 -nH) /2 = ( 5 x 2+2 -10) /2 = 1

hence 1 double bond , splitting given by N+1 wher N is number of H attached

125.5 d and 135.5 d indicates we had CH=CH ,

17.5 q means we had CH3 and 23.3 q means we had CH3 , 68.8 d means we had CH attached to O

structure is

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Answer 2

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