Question

Test if a year is a leap year. Do this by creating a function named is LeapYear. This function will not return anything it will just print (“\(year) is a leap year”) or (“\(year) is not a leap year”) (using language swift)?

a. The function should accomplish the following

b. Get user input to define a year

c. Divide the input by 4. If there is a remainder it is not a leap year.

d. Divide the input by 100. If there is no remainder it is a leap year

e. Divide the input by 400. There is a remainder the year is not a leap year. If there is no remainder it is a leap year

Answer 1

//LeapYear __FUNCTION__
func LeapYear(year: Int) -> Void {
    if year % 4 != 0 { //Divide the input by 4. If there is a remainder it is not a leap year.
        print("\(year) is not a leap year")
    } else { 
    /* Divide the input by 100. If there is no remainder it is a leap year
       Divide the input by 400. There is a remainder the year is not a leap year. 
       If there is no remainder it is a leap year */
       
        if year % 100 == 0 && year % 400 != 0 { 
            print("\(year) is not a leap year")
        } else {
            print("\(year) is a leap year")
        }
    }
}

//Taking user input
print("Enter year: ")
if let input = readLine() //user input as String
{
    if let int = Int(input) //converting user input to type Integer
    {
        LeapYear(year: int) //Calling the LeapYear __FUNCTION__
    }
    else{
        print("\(input) of not a valid Integer") //if user input is not a valid Integer
    }
}

OUTPUT

Enter year: 2014 2014 is not a leap year .. Program finished with exit code o Press ENTER to exit console.