Question

I need help with a project, I’ve seen many answers in C++, but i need it to be in swift, thank you!

Write a program that asks the user to enter a date (e.g. July 4, 2008) and will return the day of the week that corresponds to that date. Your program should take the input in numeric form, thus the input prompt should be as follows: Please enter a date below: Enter month (1-12): Enter day (1-31) Enter year (0000-9999): The following algorithm is from http://en.wikipedia.org/wiki/Calculating the day of the _week The implementation will require several functions: bool isLeapYear (int year)i This function should return true if year is a leap year and false if it is not. Here is pseudocode to determine a leap year: leap_year ((year divisible by 400) or (year divisible by 4 and year not divisible by 100) int getCenturyValue (int year): This function should take the first two digits of the year (i.e. the century), divide by 4, and save the remainder. Subtract the remainder from 3 and return this value multiplied by 2. For example, the year 2008 becomes: (20/4) -5 remainder 0. 3-0-3. Return 3 * 2 6. int getYearValue (int year) This function computes a value based on the years since the beginning of the century. First, ct the last two digits of the year. For example, 08 is extracted for 2008. Next, factor in leap years. Divide the value from the previous step by 4 and discard the remainder. Add the two results together and return this value. For example, from 2008 we extract 08. Then (8/4) 2 remainder 0. Return 2+8-10 int getMonthValue (int month, int year): This function should return a value based isLeapYear function: on the table below and will require invoking the Month Return Value 0 (6 if year is a leap year) 3 (2 if year is a leap year) anuary February3 March April May June 4 August September October November December Finally, to compute the day of the week, compute the sum of the date's day plus the values returned by getMonthValue, getYearValue, and getCenturyValue. Divide the sum by 7 and compute the remainder. A remainder of 0 corresponds to Sunday, 1 corresponds to Monday, etc. up to 6 which corresponds to Saturday. For example, the date July 4,2008 should be computed as: (day of month) + (getMonthValue) + (get Yearvalue) + (getCenturyvalue)-4 + 6 + 10 + 6 -26. 26/7 3 remainder 5. The fifth day of the week corresponds to Friday Your program should allow the user to enter any date (numerically) and output the corresponding day of the week in English. Bonus: Adjust your program so the user could re-enter a new date as many times as they wish without having to restart the program.

Answer 1

Here is mine code in C++:

#include <iostream>
#include <stdlib.h>
using namespace std;

bool checking_year(int year){

if ((year>999) && (year < 10000)){
return true;
}else{

return false;
}

}

bool checking_month(int month){
if ((month>0) && (month<13)){
return true;
}else{
return false;
}
}

bool checking_date(int day, int month){
if ((month==2) && (day>0) && (day<30)){
return true;
}
if ((
(month==1) ||
(month==3) ||
(month==5) ||
(month==7) ||
(month==8) ||
(month==10)||
(month==12)
) && ((day>0) && (day<32)))
{
return true;
}
if ((
(month==4) ||
(month==6) ||
(month==9) ||
(month==11)
) && ((day>0) && (day<31)))
{
return true;
}
return false;
}

bool isLeapYear(int year){
if (((year % 4)==0) && ((year % 100)!=0)){
return true;
}else if ((year % 400)==0){
return true;
}else {
return false;
}

}

// http://en.wikipedia.org/wiki/Julian_day#Calculation
const char *get_day(int day, int month, int year){
int JMD;
JMD = (day + ((153 * (month + 12 * ((14 - month) / 12) - 3) + 2) / 5) +
(365 * (year + 4800 - ((14 - month) / 12))) +
((year + 4800 - ((14 - month) / 12)) / 4) -
((year + 4800 - ((14 - month) / 12)) / 100) +
((year + 4800 - ((14 - month) / 12)) / 400) - 32045) % 7;
const char *weekday[] = {"Monday",
"Tuesday",
"Wednesday",
"Thursday",
"Friday",
"Saturday",
"Sunday"};
return weekday[JMD];
}

int main(){

int year, month, date, x, y;
cout << "\nPlease Enter The Year [YYYY] : ";
cin >> year;

if (checking_year(year)){
cout << "\n\tYear Verified";
}else{
cout << "\n\t Wrong Year Format\n";
exit(0);
}

cout << "\nPlease Enter The Month [MM] : ";
cin >> month;

if (checking_month(month)){
cout << "\n\tMonth Verified";
}else{
cout << "\n\t Wrong Month Format";
exit(0);
}
cout << "\nPlease Enter The Date [DD] : ";
cin >> date;

if (checking_date(date, month)){
cout << "\n\tDate Verified\n\n";
}else{
cout << "\n\t Wrong Date Format";
exit(0);
}
cout << "Date : " << date << ", Month : " << month << ", Year : " << year << " [ ";
if (isLeapYear(year)){
cout << "Leap Year" << " ]";
}else{
cout << "Not Leap Year" << " ]";
}
cout << "\n\tWeekday : ";
cout << get_day(date, month, year);
cout << "\n\n";

return 0;
}

Output:-

Please Enter The Year [YYYY] : 2019 Year Verified Please Enter The Month [MM]: 3 Month Verified Please Enter The Date [DD]: 21 Date verified Date 21, Month : 3, Year 2019 [ Not Leap Year ] Weekday : Thursday

Here is my code for Swift 3 and later:-

import Foundation
import Glibc
 
func gettingDayOfWeek(_ today:String) -> Int? {
    let formatter  = DateFormatter()
    formatter.dateFormat = "yyyy-MM-dd"
    guard let todayDate = formatter.date(from: today) else { return nil }
    let myCalendar = Calendar(identifier: .gregorian)
    let weekDay = myCalendar.component(.weekday, from: todayDate)
    return weekDay
}
if let weekday = gettingDayOfWeek("2019-03-17") {
    print(weekday)
} else {
    print("bad input")
}