Question

the instructions are: 

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 - leap year

Ex: If the input is:

1913

the output is:

1913 - not a leap year

the code given below is: I need it in C++ please!

#include

using namespace std;

int main() {

   int inputYear;

   bool isLeapYear = false;

   

   cin >> inputYear;

   

   /* Type your code here. */

   return 0;

}

Answer 1

#include 

 

using namespace std;

 

bool isLeapYear(int year)

{

   if (year % 400 == 0) {

        return true;

    }

    else if (year % 100 == 0) {

        return false;

    }

    else if (year % 4 == 0) {

        return true;

    }

    return false;

}

 

int main()

{

    int year;

    cin >> year;

    if(isLeapYear(year))

      cout << year << " - leap year"<

   else

      cout << year << " - not a leap year"<

    return 0;

}