Question

In Python 3 please

3.28 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is: 1712 the output is: 1712 - leap year

Ex: If the input is: 1913 the output is: 1913 - not a leap year

Answer 1

if __name__ == '__main__':
    year = int(input())

    is_leap_year = year % 4 == 0 and (year % 400 == 0 or year % 100 != 0)

    if is_leap_year:
        print(year, "- leap year")
    else:
        print(year, "- not a leap year")