Question

#1 Write a MATLAB script to solve: Leap Year Program (practice your IF statements!) Write a code to determine if a year is considered a leap year or not? Display to the screen if the year is a leap year or not. Use num2str() and display() or fprintf(). In the Gregorian calendar three criteria must be taken into account to identify leap years: The year is evenly divisible by 4 (Exceptions 1700, 1800, and 1900); If the year can be evenly divided by 100, it is NOT a leap year, unless; The year is also evenly divisible by 400. Then it is a leap year.

Answer 1

Note that every year that is exactly divisible by 4 is a leap year, except for years that are exactly divisible by 100. However, years that are exactly divisible by 400 are also leap years. For example, the year 1900 was not leap year, but the year 2000 was.

SOLUTION IS HERE

function valid = valid_date(year,month,day)
t = (isscalar(year) && isscalar(month) && isscalar(day));
if (t == 0);
valid = t;
else
T = ((nargin == 3) && (year>0) && ((month > 0) && (month <=12)) && ((day > 0) && (day<=31)));
if T
persistent Div_by_Four;
persistent Div_by_FHun;
persistent div_by_hund;
persistent leap_year;
leap_year=0;
Div_by_Four = rem(year,4);
Div_by_FHun = rem(year,400);
div_by_hund = rem(year,100);
if (Div_by_Four == 0)
leap_year = 1;
end
if (div_by_hund == 0)
leap_year = 0;
end
if (Div_by_FHun == 0)
leap_year = 1;
end
if (leap_year == 1 && month == 2)
valid = day<=29;
  
elseif (month<=7)
if(month == 2)
valid = day<=28;
elseif (rem(month,2) == 0)
valid = day<=30;
else
valid = day<=31;
end
else
if (rem(month,2) == 0)
valid = day<=31;
else
valid = day<=30;
end
end
else
valid = T
end
end