A lab procedure calls for 150 mL of a 2.5 M solution of HNO3. How should...

Question

Question

science chemistry

Answer 1

Answer #1

M1V1 = M2V2

M1 = 18 M

V1 = ?

M2 = 2.5 M

V2 = 150 mL = 0.150 L

On substituting

V1 = 2.5 x 0.15/18 = 0.0208 L

0.0208 L 18 M HNO3 and 0.129 L water. Option C is the correct answer

Answer 2

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