What volume of 0.172M lithium phosphate reacts with 95.4 mL of 0.102 M copper (II) bromide...

Question

Question

science chemistry

Answer 1

Answer #1

2Li3PO4 +3 CuBr2 -------------> Cu3(PO4)2_(s) + 6 LiBr_(aq)

mass of solid product = 3.70 g

moles of product = 3.70 / 380.58 = 0.0097

according to balanced reaction

1 mole solid product require 2 moles Li3PO4

0.0097 moles solid product require 0.0097 x 2 = 0.0194 moles Li3PO4

moles = Molarity x V in L

0.0194 = 0.172 x V

V = 0.113 L = 113 mL

volume of Li3PO4 require = 113 mL

Answer 2

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