Answer:
Here, +++ and abc are parental and we need to calculate the distance between a-c and c-b in cm unit. The formuli are-
a-c = 100*[(+bc)+(a++)+(++c)+(ab+)]/3000
=100* [94+111+96+103]/3000
= 13.46 cm
c-b= 100*[(+b+)+(a+c)+(++c)+(ab+)]/3000
= 100*[621+695+96+103]/3000
=50.5
The map distance will be=
b--------------------37.04cM-------------------------a----------13.46cM-----------c
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