Question

Consider the reaction. A(aq) = 3 B(aq) K. 2.00 x 10-6 at 500 K If a 3.60 M sample of A is heated to 500 K, what is the concentration of B at equilibrium? [B] =

Answer 1

Solution:- Given reactiem is : Alag.) ² 3 B pq.) Kc = 2.00 x 10b Temperature = 5ook Also, Initial concentration of A = 3.60 M Let 'X'M dissociated at Equilibrium Then, be 3 Blago) Alaq) Initial concentration. 3.60 At Equilibrium concentration : 3.6o-x 3x 3 Also, Re = [B] [A where [B] and [A] are Concentration of B and A- At Equilibriumi (B) = 39 ; [A]> 3.60 -

1 Ke= (3x33 2100 X 106 (3.60 -x] Since, Kc = 2.00x106 is very small Therefore 3. reaction will shift in forward direction to form small amount of B. So, 's mi will be small respect 3.60 M. Then neglecting in denominator equation o We have very s with to re in

(372)3 2.00 x10-6 3.60 or, 27a3 3.60 x 2.0 X10 Lox106 2793. or, 7.2 x 1 x 106 3 0.2667 x 106 OY 26 72x10-6 2 Glo 5 ) 6 or (0.2667x100 Taking cube root we get = 0.644 XI Lx102 or, x = 6.44 x 103 M B = [B] = 3x 3 x 6.4 uxlol concentration of M 3 10 M or , [B] : 1.932 x :. Concentration of B = 1.932 x 10 3M [ B] - 11-932 1.932 x 103 m Ans is v Note:- Clearly value of [B] = 1.932 x10?m with respect to very small 3:60m
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