Question

The Earth’s magnetic field, B = 5.00 x 10^-5 T, points into the page as shown below, and is parallel to the Earth’s surface. An electron is moving with a constant velocity v = 5.00 x 10⁶ m/s to the right in a straight horizontal path between the two charged parallel plates of a capacitor of area 10.0 m² with plates separated by a distance of 5.00 x 10^-3 m.

How much charge is on each of the plates? Give answer in units of nC (nano-coulombs) to 3 significant figures.

B X X X х X 12 X X Capacitor Plates х X X х x х х T Earth

Answer 1

solution Let Q = and Q = Charge on the upper plate in ne Charge on the lower Plate in ne ne 1010 So Electric field in between the two So + m2 Plates = E directed Q lo to - E co fromupberto lower Plake. Fe so the force on the electron е Е Fe= directed lo to from lower to upperplate. on the electroni Im Be v directed from Magnetic force Fm upper to lower Plate. As eleckon moves Horizontally undeflecteel Bev so Q = 1o COX BXV lox 8,858 10 12x 500 oxlor x yooo x106 C 22.125 10-9 c 22.125 nes 22.1 nc И С 22.1 Ø