Question

JAVA:

(15 marks) Write a program that creates an integer array with 50 random values, prompts the user to enter the index of an element in the array between 0 and 49, then displays the corresponding element value. If the specified index is out of bounds, display an error message (e.g. "Out of Bounds") and ask the user to enter another index. Use a while loop that will keep prompting the user until a valid input is received. To handle invalid inputs, write two versions of your program: one that uses exception handling, and one that uses defensive programming. Assume a user will always enter numbers. Verify that the displayed element number is indeed from the index number entered Sample run: list[50] of random int generated 27 43 63 34 74 3 50 25 92 82 72 36 72 25 11 57 3 0 0 74 21 59 70 24 4 51 67 15 67 92 96 90 56 52 17 75 51 87 24 87 78 72 14 91 10 64 59 27 82 89 Enter an index: 99 Out of Bound. Try again:50 Out of Bound. Try again:7 The element is 25

Answer 1

import java.util.Random;
import java.util.Scanner;

public class RandomArray {
   public static void main(String[] args) {
       int arr[]=new int[50];
       Random r = new Random();
       for(int i=0;i<arr.length;i++) {
           arr[i]=r.nextInt(100);
           System.out.print(arr[i]+" ");
           if(i!=0 && i%10==0)
               System.out.println();
       }
       Scanner sc = new Scanner(System.in);
       int index;
       System.out.print("\nEnter an index: ");
       index=sc.nextInt();
       while(index<0 || index>=50) {
               System.out.print("Out of Bound. Try again: ");
               index=sc.nextInt();
       }
       System.out.println("The element is "+arr[index]);
   }
}

49 70 4 21 70 14 15 74 9 28 76 7 66 23 53 68 82 59 63 3 78 83 54 40 88 7 19 69 15 4 97 91 97 13 53 52 38 46 77 48 32 87 6 20 81 46 17 64 Enter an index: 122 Out of Bound. Try again: 200 Out of Bound. Try again: 39 The element is 46

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