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Given the first order initial value problem y 2y -48(t -2), y(03 Let Y(s) denote the Laplace transform of y. Then Y(s) = Taki

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Given y, + 2y = 4δ(-2) → (1), y(0)--3 Applying Laplace transform to(1), we get し{y] +2E(») = 4L@c-2) (sY(s)-y@)) +27(s) = 4e-

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