Question

Use a while-end loop in a script file to calculate the sum of the first n terms of the series: sigma_k=1^n (-1)^kl^2 + 5k/3^k. Show the script file and the two results of n = 10 and n = 20. (b) Use a for-end loop in a script file to calculate the sum of the first n terms of the series: sigma_k=1^n (-1)^kl^2 + 5k/3^k. Show the script file and the two results of n = 10 and n = 20.

Answer 1

In the following I'm adding the scripts along with sample output which solves the requirements Part a: Coding function [output]- Summation (n) disp(['for n -'num2str (n)]) sumI 0; while n>0 sum1 sum1 + (((-1)."n*n."2 + 5*n )/3. ^n); = end output = sumi; end Summation (10) Summation (20) Output sh-4.3 octave -qf --no-window-system demo.m octave: X11 DISPLAY environment variable not set octave: disabling GUI features warning: function ./demo.m shadows a core library function for n =10 ans 3。6563 for n20 ans3.6563 sh-4.3$ Part b: Coding function output]-Summation (n) disp(I'for n-' num2str (n)]) sum 0; for k-1:1:n sum1 sum1 + (((-1) ."k* k . ^2 + 5*k )/3."k); = end outputu end Summation (20) Output sh-4.3 octave -qf --no-window-system demo.m octave: X11 DISPLAY environment variable not set octave: disabling GUI features warning: function ./demo.m shadows a core library function for n = 10 ans 3 " 6563 for n20 ans3.6563 sh-4.3$

function [output] = Summation(n)

    disp(['for n = ' num2str(n)])

    sumI = 0;

    while n>0

        sumI = sumI + (((-1).^n*n.^2 + 5*n )/3.^n);

        n=n-1;

    end

    output = sumI;

end

Summation(10)

Summation(20)

%--------------------------------------------

function [output] = Summation(n)

    disp(['for n = ' num2str(n)])

    sumI = 0;

    for k=1:1:n

        sumI = sumI + (((-1).^k*k.^2 + 5*k )/3.^k);

    end

    output = sumI;

end

Summation(10)

Summation(20)