Question

ES APERTURES LEO Question 12. 0.16 0.08 LASER SINGLE SLITS 0.02 0.04 VARIABLE Single-slit disk 3 0.02 to 0.20 Figure 1 PASCO HIGH PRECISION DIFFRACTION SLITS SINGLE SLITS SQUARE HEX BNN Laser light (a = 635 nm) passes through one slit, as shown above. - A single-slit is selected from a disc that looks like figure 2: - It is assumed that the chosen values of the double slot are : - a= 0.04 mm - And the distance R=1.32 m Ins/zNI1 Sinon SLOO SNYBLIV Figure 2 This result is obtained on a milimetric paper (each small line is Imm): mdif=2 dif min mdif=-1 mdir=1 dif min dif min The central maximum is at location y=0. The y-location of the dif mins can be found from the figure The central maximum (y=0) is in between the m=1 and m=-1 dif mins We know that locations of diffraction minimas are defined by: a*sin0 = mà a) Find where the centre of central maximum (y=0) is and call this position y=0 m. b) Find the position of the two diffraction minima (m=1 & m=2) that are above the central maximum. c) Calculate the theoretical position of these interference maxima (m=1 & m=2) using the equation to find the angle relative to it, then trigonometry to find the y-position. Find the percentage error for each relative to the experimental value found in step 2. d) Demonstrate all your work for the calculations of m=1. You can simply show the final answer for the other.

Answer 1

SINGLE SLIT INTERFERENCE

GIVEN: $\lambda$ = 635*10^-9 m

a = 0.04*10^-3m

R = 1.32 m

condition for maximum,

y = (m*$\lambda$*R) / a

(a) The catre of the Chatusel maximum is located at yzom. (b) The position of m=182 by rading the graph, m=i eg = 1.9cm m=2, 42 = 4 cm (c) Theoretical Values form=1&2. y = mar زرد رد = ۷ 1 x 6358159x 1.32 0.04 X 103 Mi = 2.09 cm m=2, 2= 2 x 6350)5?X).32 0²04 X 103 G2 = 4.19cm perchtage difperence between af, 7 y, and 428 4² For m=2, y = 11.9-2.89L x 100 =9.52% (19+2.09) Form= 2, y = 14-4.1918100=4.63% +4 19 11) (4+4