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2) Let G ME) be an undirected Graph. A node cover of G is a subset U of the vertex set V such that every edge in E is incident to at least one vertex in U. A minimum node cover MNC) is one with the lowest number of vertices. For example {1,3,5,6is a node cover for the following graph, but 2,3,5} is a min node cover Consider the following Greedy algorithm for this problem: Algorithm NodeCover (V,E) Uempty While E <> empty Find a vertex v of maximum degree v=v-v E = E - la.x} for all {Χ.Χ} such that x = v or y = v a) b) Give a graph example (other than the above graph) where this algorithm generates a MNC Give a graph counter-example to prove that this algorithm does not always generate the MNC.

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Answer #1

a) Consider the graph with 4 vertices, where V = \{1, 2, 3, 4\}, E = \{(1,4),(2,4),(3,4)\} . Then the algorithm will simply choose \{4\} as the minimal set cover, which is indeed correct, as all edges are incident on 4 .

b) Consider the graph with 7 vertices where V = \{1, 2, 3, 4, 5, 6, 7\}, E = \{(1,2),(1,3),(1,4),(2,5),(3,6),(4,7)\} .

In this case the algorithm will pick 1 first, after which the remaining edges will be \{(2,5),(3,6),(4,7)\} . Now 3 more vertices need to be picked for the vertex cover, which means a total of 4 vertices in the cover.

While, the optimal solution is picking \{2,3,4\} , which is of size 3, better than the one chosen by the greedy algorithm.

Comment in case of any doubts.

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