A current I = 19.0 A flows through a strip of metal of width 3.5 cm...
A current I = 19.0 A flows through a strip of metal of width 3.5 cm (the figure below). An electromagnet is switched on so that there is a uniform magnetic field of magnitude 0.49 T directed into the page, and the Hall voltage is measured to be 6.3
Homework Answers
rate of flow
through the strip
rate of flow = density (concentration) X cross sectional area X
linear velocity of the fluid
Q = d*A*v where d = density
this should give
v= 19amps / (12.25 X 10^4 sq m X 6.3 X 10^28 X .49)=
=5.024*10^39mm/s
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A current
I
= 19.0
A flows through a strip of metal of width 3.5
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Calculate the speed v.
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length of 18.5 cm and a width of 9.0 cm containing 14 loops lies
flat on your desk as shown on this page. A uniform magnetic field
of magnitude 5.10 × 10 − 5 T points towards the left of this page.
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